Replaces a line with the contents of another file… here is a solution to the problem.
Replaces a line with the contents of another file
I have a question. I want to replace a line of one file with the contents of another file.
In my first file, I have this line: "#Content"
, which I want to replace with the contents of the file content.xml
.
Thank you.
Solution
This works :
your_new_text=$(cat content.xml | sed 's/[^-A-Za-z0-9_]/\\&/g')
sed -i "s/#Content/$your_new_text/" your_file
It puts the text in content.xml
into the variable $your_new_text
. Then sed does the job: -i
stands for replacement in the file, looks for #Content
and replaces with text in $your_new_text
.
Note that it must be wrapped with "
Parcel to work.