Java.sql.SQLException : Result set after last row exception

I

think I’m having trouble because of this line in the RequestDaoImpl class mentioned below rs.next(); 。 Whenever I try to retrieve the value of STATUS, I keep getting the following error:

java.sql.SQLException: The result set follows the last line

What am I doing wrong here?

  @Component
    public class GetStatus {

@JmsListener(destination = "Queue1")
        public void processStatusMessage(String message) throws DaoException {

System.out.println("Message Retrieved is:" +message);

try {

RequestDao requestDao = (RequestDao) context.getBean("requestDao");

String receivedStatus = requestDao.getRequestStatus(message);

System.out.println("Testing March 11");
            System.out.println(receivedStatus);

}
            catch(Throwable th){
                th.printStackTrace();   

}

}

private static ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext("ApplicationContext.xml");

}

My RequestDao is:

public interface RequestDao {

public String getRequestStatus(String msg)throws DaoException;

}

My RequestDaoImpl method implementation:

public class RequestDaoImpl implements RequestDao {

public void setDataSource(DataSource dataSource) 
    {       
        jdbcTemplate = new JdbcTemplate(dataSource);                                    
    }

@Override
    public String getRequestStatus(String msg) throws DaoException {
        DataSource ds = null;
        Connection conn = null;
        PreparedStatement pstmt = null;
        ResultSet rs = null;
        String requestStatus = null;

List<String> mylist = new ArrayList<String>();

try {

ds = jdbcTemplate.getDataSource();
                conn = ds.getConnection();  

I am receiving message like this hence splitting it : 123456#Tan#development
                 String[] parts =   msg.split("#");
                 String requestID = parts[0].trim();
                 String userName =  parts[1].trim();
                 String applicationName = parts[2].trim();

/*===========================================================================*/
                /*    Code to get the request status from Mytable          */ 
                /*===========================================================================*/
                pstmt = conn.prepareStatement("SELECT STATUS FROM Mytable WHERE request_user= ? and app_name =? and request_id=?");
                pstmt.setString(1,userName);
                pstmt.setString(2,applicationName);
                pstmt.setString(3, requestID);
                rs = pstmt.executeQuery();  
                rs.next();
                System.out.println("The status received is as follows:");

requestStatus = rs.getString("STATUS");
                System.out.println(requestStatus);

}
         catch(Throwable th) {
                throw new DaoException(th.getMessage(), th);
            }
            finally {
                if (rs != null) { try { rs.close(); } catch (SQLException e) { e.printStackTrace(); }}
                if (pstmt != null) { try { pstmt.close(); } catch(SQLException sqe) { sqe.printStackTrace(); }}
                if (conn != null) { try { conn.close(); } catch (SQLException sqle) { sqle.printStackTrace(); }}

}   

return requestStatus;
    }
  private JdbcTemplate jdbcTemplate;    
 }

Saw similar errors in the here post, but their code is different from mine.

This may be because no rows were fetched.
ResultSet#next returns a boolean value indicating whether a row exists.

What you need to apply for is a condition that checks the condition.
Since you need a line, if is a great fit.

if (rs.next()) {
   ...
   requestStatus = rs.getString("STATUS");
   ...
}

Note that your queries can be optimized by applying keywords that rely on the DBMS, such as MySQL's LIMIT

SELECT STATUS FROM Mytable WHERE request_user= ? and app_name =? and request_id=? LIMIT 1