Java – Open files in android using the default application

I’m making a file explorer in android. So I want to get a suggestion of an application that can open it when clicking on any file outside of the directory, and a dailog that shows if there is no application. I tried some solutions but nothing worked, so, for now, I’m just showing that the file isn’t a directory in the toast

Part of the code is as follows:

protected void onListItemClick(ListView l, View v, int position, long id) {
    String filename = (String) getListAdapter().getItem(position);
    if (path.endsWith(File.separator)) {
        filename = path + filename;
    } else {
        filename = path + File.separator + filename;
    }
    if (new File(filename).isDirectory()) {
        Intent intent = new Intent(this, ListFileActivity.class);
        intent.putExtra("path", filename);
        startActivity(intent);
    } else {
        Toast.makeText(this, filename + " is not a directory", Toast.LENGTH_LONG).show();
    }
}

Android has some built-in Intent Action Type This can help you open or view a specific file, but for this you need to know the type of file you want to work with.

Assume that you have a file type that can be categorized by using document types

ACTION_OPEN_DOCUMENT has a specific MIME_TYPE (Android 4.4 or later).

Or if you are going to process some media files (audio/video).

You can use it

ACTION_VIEW

To identify the MIME_TYPE of a specific file, you can use functions

guessContentTypeFromName (string url). Link

or getMimeTypeFromExtension <a href="http://developer.android.com/reference/android/webkit/MimeTypeMap.html#getMimeTypeFromExtension( java.lang.String)" rel="noreferrer noopener nofollow">Link