Java – Why use an extra var2-byte array in the hashCode method of the StringLatin1 utility class?

The current code is:

public static int hashCode(byte[] value) {
    int h = 0;
    byte[] var2 = value;
    int var3 = value.length;

for(int var4 = 0; var4 < var3; ++var4) {
        byte v = var2[var4];
        h = 31 * h + (v & 255);
    }

return h;
}

The possible code is:

public static int hashCode(byte[] value) {
    int h = 0;
    int var2 = value.length;

for(int var3 = 0; var3 < var2; ++var3) {
        byte v = value[var3];
        h = 31 * h + (v & 255);
    }

return h;
}

In the java.lang package, there is a utility class called StringLatin1. This class has a hashCode method that is called from the hashCode method of the String class if the current string value is Latin.

PS: I use Java 11.

Whatever the current code you release is, it’s not real code; It is decompiled code and may vary from decompiler to decompiler, so you cannot rely on it.